Thanks, Tale. The "slider1:0<0,1,1>Switch" solution was the first I tried but to get it to the right you have to grab the slider rather than clicking to the right of it. It goes back left with a click though so I figured I was just not doing it right. I had the yes/no pull down but didn't like it because I want to use it as an enable/disable function that happens when you click on it. The intermediate list is just not the way the function should work and feels wrong if you are trying to do A/B comparison. I just had an inspiration that got your last solution to work! Define the slider as: Code:
Tales method above is the correct way ... But i've created two position sliders like this: slider2:4<4,20,16>Comp/Limit Its a slider, but only has two positions.
Greetings, If it can't be a graphical switch, I'm afraid there is no other way as already proposed. JSFX default gui only supports sliders or select boxes and the logic they operate is 'hard wired'. Or at least I'm not aware of anything else. If you use jsfx gfx abilitites, there is no limit what you can do. Sliders, knobs, buttons,...
Using the method above where I slam the slider to either end in @slider I have no problem clicking on either side to make it work. The one Aeolian suggests does nothing when I do the exact same thing. I can't figure out what triggers might be useful for other than possibly debug. I can't imagine a user dealing with a row of ten unnamed blocks.
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Glad it works for you. Is it possible that what you do with it further on in the plug gives rise to the behavior you show rather than being inert like it is when I only include the slider line?
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